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C++ AND DATA
STRUCTURE
/*1. Write a program to find the frequency
of presence of an element in an array*/
#include<iostream.h>
#include<conio.h>
class
frequency
{
int
a[10],n,i,ele;
public: void
getdata();
void putdata();
};
void
frequency::getdata()
{
cout<<"Enter
the size of an array";
cin>>n;
cout<<"Enter
the elements\n";
for(i=0;i<n;i++)
cin>>a[i];
}
void
frequency::putdata()
{
int count=0;
cout<<"Enter
the element whose frequency is to be checked: ";
cin>>ele;
for(i=0;i<n;i++)
if(ele==a[i])
count++;
cout<<ele<<"
has appeared "<<count<<" times";
}
void main()
{
frequency f;
clrscr();
f.getdata();
f.putdata();
getch();
}
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/* 2. Write a program to insert an element
into an array at a given position.*/
#include<iostream.h>
#include<conio.h>
void main()
{
int
a[10],i,n,ele,p;
cout<<"Enter
the size of an array: ";
cin>>n;
cout<<"Enter
the elements:\n";
for(i=0;i<n;i++)
cin>>a[i];
cout<<"Enter
the element to be inserted: ";
cin>>ele;
cout<<"Enter
the position (from 0 to "<<n<<")";
cin>>p;
if(p>n)
cout<<"Invalid
Position";
else
{
for(i=n-1;i>=p;i--)
a[i+1]=a[i];
a[p]=ele;
n=n+1;
}
cout<<"Elements
after insertion are:\n";
for(i=0;i<n;i++)
cout<<a[i];
getch();
}
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/* 3. Write a program to delete an element
from an array from a given position.*/
#include<iostream.h>
#include<conio.h>
void main()
{
int
a[10],i,n,ele,p;
clrscr();
cout<<"Enter
the size of an array: ";
cin>>n;
cout<<"Enter
the elements:\n";
for(i=0;i<n;i++)
cin>>a[i];
cout<<"Enter
the position (from 0 to "<<n-1<<")";
cin>>p;
if(p>n-1)
cout<<"Invalid
position";
else
{
ele=a[p];
for(i=p;i<n;i++)
a[i]=a[i+1];
n=n-1;
cout<<"Elements
after deletion are:\n";
for(i=0;i<n;i++)
cout<<a[i];
}
getch();
}
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/* 4. Write a program to sort the elements
of an array in ascending order using an insertion sort.*/
#include<iostream.h>
#include<conio.h>
void main()
{
int
a[10],i,j,n,temp;
clrscr();
cout<<"Enter
the size of an array: ";
cin>>n;
cout<<"Enter
the elements:\n";
for(i=0;i<n;i++)
cin>>a[i];
for(i=1;i<n;i++)
{
temp=a[i];
j=i-1;
while(temp<a[j]&&j>=0)
{
a[j+1]=a[j];
j=j-1;
}
a[j+1]=temp;
}
cout<<"Sorted
elements are:\n";
for(i=0;i<n;i++)
cout<<a[i];
getch();
}
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/* 5. Write a program to search for a given
element in an array using Binary search method. */
#include<iostream.h>
#include<conio.h>
void main()
{
int
a[10],i,n,ele,pos=-1,m,b,e;
clrscr();
cout<<"Enter
the size of an array: ";
cin>>n;
cout<<"Enter
the elements:\n";
for(i=0;i<n;i++)
cin>>a[i];
cout<<"Enter
the search element: ";
cin>>ele;
b=0;
e=n-1;
while(b<=e)
{
m=(b+e)/2;
if(ele==a[m])
{
pos=m;
break;
}
else
if(ele<a[m])
e=m-1;
else
b=m+1;
}
if(pos>=0)
cout<<"Location="<<pos;
else
cout<<"Search
is unsuccessful";
getch();
}
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/* 6. Write a program to create a class
with data member principal, time and rate. Create member functions to accept
data values to compute simple interest and to display the result*/
#include<iostream.h>
#include<conio.h>
class SI
{
int time;
float
principal,rate;
public: void
getdata()
{
cout<<"Enter the
principal, time and rate of interest: \n";
cin>>principal>>time>>rate;
}
float compute_si()
{
return(principal*time*rate/100.0);
}
void display()
{
cout<<"Simple
Interest="<<compute_si();
}
};
void main()
{
SI s;
clrscr();
s.getdata();
s.display();
getch();
}
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/* 7. Write a program to create a class
with data members a, b, c and member
functions to input data, compute the
discriminant based on the following
conditions and print the roots.
- if discriminant=0, print the roots that
are equal
- if the discriminant is>0, print the
real roots
- if the discriminant is<0, print that
the roots are imaginary*/
#include<iostream.h>
#include<conio.h>
#include<math.h>
class quad
{
float
x1,x2,imaginarypart,realpart,discriminant,a,b,c;
public: void
getdata()
{
cout<<"Enter the values
of a, b, c: ";
cin>>a>>b>>c;
discriminant=b*b-4*a*c;
}
void putdata()
{
if(discriminant>0)
{
x1=(-b+sqrt(discriminant))/(2*a);
x2=(-b-sqrt(discriminant))/(2*a);
cout<<"Roots are real and
different:\n";
cout<<"x1="<<x1<<"and
x2="<<x2;
}
else if(discriminant==0)
{
x1=-b/(2*a);
cout<<"Roots are real and
equal\n";
cout<<"x1=x2="<<x1;
}
else
{
realpart=-b/(2*a);
imaginarypart=sqrt(-discriminant)/(2*a);
cout<<"Roots are
imaginary\n";
cout<<realpart<<"+"<<imaginarypart<<"i"<<endl;
cout<<realpart<<"-"<<imaginarypart<<"i";
}
}
};
void main()
{
quad q;
clrscr();
q.getdata();
q.putdata();
getch();
}
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/* 8. Program to find the area of a
square/rectangle/triangle using function overloading.*/
#include<iostream.h>
#include<conio.h>
class
function_overloading
{
public: int
area(int a) // area of a square
{
return(a*a);
}
int area(int l,int w) // area of a
rectangle
{
return(l*w);
}
double area(double b,double h)
{
return(0.5*b*h);
}
};
void main()
{
function_overloading
f;
clrscr();
cout<<"Area
of square="<<f.area(5)<<endl;
cout<<"Area
of rectangle="<<f.area(5,10)<<endl;
cout<<"Area
of triangle="<<f.area(2.0,3.0);
getch();
}
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/* 9. Program to find the cube of a number
using inline functions.*/
#include<iostream.h>
#include<conio.h>
inline int
cube(int a)
{
return(a*a*a);
}
void main()
{
int x,y;
clrscr();
x=cube(5);
cout<<"Cube
of 5="<<x<<endl;
y=cube(10);
cout<<"Cube
of 10="<<y;
getch();
}
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/* 10. Write a program to find the sum of
the series 1+x+x^2+...+x^n using constructors.*/
#include<iostream.h>
#include<conio.h>
class series
{
int x,n;
public:
series(int x1,int n1)
{
x=x1;
n=n1;
}
void display();
};
void
series::display()
{
int sum=1;
for(int
i=0;i<n;i++)
{
sum=sum*x;
sum=sum+1;
}
cout<<"Sum
of the series 1+x+x^2+...+x^n="<<sum;
}
void main()
{
int x1,n1;
clrscr();
cout<<"Enter
the value of x: ";
cin>>x1;
cout<<"Enter
the value of n: ";
cin>>n1;
series
s(x1,n1);
s.display();
getch();
}
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/* 11. Create a base class containing the
data members roll number and name. Also create a member function to read and
display the data using the concept of single level inheritance. Create a
derived class that contains marks of two subjects and total marks as the data
members.*/
#include<iostream.h>
#include<conio.h>
class abc
{
int rollno;
char
name[20];
public:
void read()
{
cout<<"enter roll no and
name"<<endl;
cin>>rollno>>name;
}
void display()
{
cout<<"roll
no:"<<rollno<<endl;
cout<<"name:"<<name<<endl;
}
};
class
xyz:public abc
{
int m1;
int m2;
int t;
public:
void read1()
{
cout<<"enter the first
marks & second marks:";
cin>>m1>>m2;
t=m1+m2;
}
void display1()
{
cout<<"first
marks="<<m1<<endl;
cout<<"second
marks="<<m2<<endl;
cout<<"total
marks="<<t<<endl;
}
};
void main()
{
xyz ob;
clrscr();
ob.read();
ob.read1();
ob.display();
ob.display1();
getch();
}
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/* 12. Create a class containing the
following data members register No., name and fees. Also create a member
function to read and display the data using the concept of pointers to
objects.*/
#include<iostream.h>
#include<conio.h>
class student
{
int regno;
char
name[20];
float fees;
public: void
read();
void display();
};
void
student::read()
{
cout<<"enter
the register number: ";
cin>>regno;
cout<<"enter
the student name: ";
cin>>name;
cout<<"enter
the fees: ";
cin>>fees;
}
void
student::display()
{
cout<<"register
number="<<regno<<endl;
cout<<"student
name="<<name<<endl;
cout<<"student
fees="<<fees;
}
void main()
{
student
s,*sp;
sp=&s;
clrscr();
sp->read();
sp->display();
getch();
}
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/* 13. Write a program to perform push items
into the stack.*/
#include<iostream.h>
#include<conio.h>
#include<stdlib.h>
#define N 5
void main()
{
int
stack[N],i,choice=1,top=-1,ele;
clrscr();
while(choice)
{
cout<<"\nSTACK
OPERATIONS\n\n";
cout<<"1.Push\n2.Display\n3.Exit\n";
cout<<"Enter
your Choice:";
cin>>choice;
switch(choice)
{
case
1:cout<<"Enter the element to be pushed:";
cin>>ele;
if(top==N-1)
{
cout<<"Stack
is Full";
getch();
exit(0);
}
else
{
cout<<ele<<"
is inserted at "<<top+1;
top=top+1;
stack[top]=ele;
break;
}
case
2:cout<<"Content of Stack is:\n";
if(top==-1)
{
cout<<"Stack
is Empty";
getch();
}
else
{
for(i=top;i>=0;i--)
cout<<"Stack["<<i<<"]="<<stack[i]<<endl;
break;
}
case
3:exit(0);
break;
default:cout<<"Invalid
choice";
}
}
getch();
}
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/* 14. Write a program to pop elements from
the stack.*/
#include<iostream.h>
#include<conio.h>
#include<stdlib.h>
#define N 5
void main()
{
int
stack[N]={10,20,30,40,50};
int
choice=1,ele,top=4,i;
clrscr();
while(choice)
{
cout<<"\nSTACK
OPERATIONS:\n\n";
cout<<"\n1.Pop\n2.Display\n3.Exit\n";
cout<<"\nEnter
your choice: ";
cin>>choice;
switch(choice)
{
case 1:
if(top==-1)
{
cout<<"Stack is
empty";
getch();
continue;
}
else
{
for(i=top;i>=0;i--)
ele=stack[top];
cout<<"The popped element
is: "<<ele;
top=top-1;
}
break;
case 2:
if(top==-1)
{
cout<<"Stack is
empty";
getch();
exit(0);
}
else
{
cout<<"Content of stack
is:\n";
for(i=top;i>=0;i--)
cout<<"stack["<<i<<"]="<<stack[i]<<endl;
}
break;
case 3:
exit(0);
default:
cout<<"Invalid choice";
}
}
getch();
}
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/* 15. Write a program to perform enqueue
and dequeue.*/
#include<iostream.h>
#include<conio.h>
#include<stdlib.h>
#define N 5
void main()
{
int
q[N],front=-1,rear=-1,choice=1,item,i;
clrscr();
while(choice)
{
cout<<"\n
QUEUE OPERATIONS:\n";
cout<<"\n1.INSERT\n2.DELETE\n3.DISPLAY\4.EXIT\n";
cout<<choice;
switch(choice)
{
case 1:
if(rear==N-1)
{
cout<<"\nQueue is
full";
continue;
}
else
{
cout<<"Enter the element
to be inserted: ";
cin>>item;
rear=rear+1;
q[rear]=item;
cout<<item<<" is
inserted at q["<<rear<<"]="<<q[rear]<<endl;
if(front==-1)
front=front+1;
}
break;
case 2:
if(front==rear)
{
front=-1;
rear=-1;
cout<<"\nQueue is
empty";
}
else
{
item=q[front];
cout<<"The element
deleted from "<<front<<" position is "<<item;
front=front+1;
}
break;
case 3:
if(front==-1)
{
cout<<"\nQueue is
empty\n";
continue;
}
else
{
cout<<"\nStatus of
Queue:\n";
for(i=front;i<=rear;i++)
cout<<"q["<<i<<"]="<<q[i]<<endl;
}
break;
case 4:
exit(0);
break;
default:
cout<<"Invalid Choice";
}
}
}
getch();
}
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/* 16. Write a program to create a linked
list and appending nodes.*/
i) VALUE INSERTION:
ii) CALCULATION OF ELECTRICITY BILL
iii) COMPUTE AND DISPLAY DUE DATE AS BILLING DATE+15 DAYS
SQL>update ebill set due_date=bill_date+15;
i) VALUE INSERTION:
ii) CALCULATION OF TOTAL AND PERCENTAGE:
iii) COMPUTE RESULT:
iv) a) DISPLAY THE CONTENT OF THE TABLE:
SQL>select * from student;
b) QUERY TO DISPLAY THE LIST OF STUDENTS WHO HAVE PASSED:
SQL>select * from student where result=’pass’;
c) QUERY TO DISPLAY THE LIST OF STUDENTS WHO HAVE FAILED:
SQL>select *from student where result=’fail’;
d) COUNT THE NUMBER OF STUDENTS WHO HAVE PASSED:
i) FIND THE NAMES OF ALL EMPLOYEES WHO WORK FOR COMPUTER DEPARTMENT:
a) SQl>select ename from employee where dept_name=’computer’;
b) HOW MANY EMPLOYEES WORK FOR COMPUTER DEPARTMENT:
SQL>select count(*) from employee where dept_name=’computer’;
ii) USE OF AGGREGATE FUNCTIONS:
a) SQL> select min(salary),max(salary),avg(salary) from employee where dept_name=’computer’;
b) SQL>update employee set salary=salary+10*salary/100 where dept_name=’computer’;
c) SQL>alter table employee add(commission number(6,2));
d) SQL>update employee set commission=5*salary/100;
e) SQL>select * from employee;
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20.
Create database for the bank transaction.
BANK TABLE CREATION:
SQL>create table bank(ac_number number(15),c_name varchar(20),ac_type char(2), balance number(15), dot date, t_amount number(15),t_type char(1));
VALUE INSERTION:
i) FIND THE NAMES OF ALL CUSTOMERS WHOSE BALANCE AMOUNT IS MORE THAN 100000
SQL>select * from bank where balance>100000;
ii) FIND THE NUMBER OF CUSTOMERS WHOSE BALANCE IS LESS THAN MINIMUN i.e. MINIMUM BALANCE IS 1000:
SQL>select count(*) from bank where balance <1000;
iii) TRANSACTION:
SQL>update bank set balance=balance+t_amount where t_type=’D’;
SQL>update bank set balance=balance-t_amount where t_type=’W’;
iv) DISPLAY TRANSACTION ON A PARTICULAR DAY:
SQL>select * from bank where dot=’12-jun19’;
v) DISPLAY ALL THE RECORDS OF SB ACCOUNT:
SQL>select * from bank where ac_type=’sb’;
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<!22. Create an HTML program with table and form.>
#include<iostream.h>
#include<conio.h>
class
linklist
{
struct Node
{
int data;
Node*link;
}*START;
public:linklist();
void print();
void Append(int num);
void count();
};
linklist::linklist()
{
START=NULL;
}
void
linklist::print()
{
if(START==NULL)
{
cout<<"linked
list is empty\n";
return;
}
cout<<"\nlinked
list contains";
Node*p=START;
while(p!=NULL)
{
cout<<p->data<<"
";
p=p->link;
}
}
void linklist::Append(int
num)
{
Node
*newNode;
newNode=new
Node;
newNode->data=num;
newNode->link=NULL;
if(START==NULL)
{
START=newNode;
cout<<num<<"is
inserted as the first node";
}
else
{
Node
*p=START;
while(p->link!=NULL)
p=p->link;
p->link=newNode;
cout<<endl<<num<<"is
inserted"<<endl;
}
}
void
linklist::count()
{
Node*p;
int c=0;
for(p=START;p!=NULL;p=p->link)
c++;
cout<<endl<<"number
of elements in the linked list="<<c<<endl;
}
void main()
{
linklist
*obj=new linklist;
clrscr();
obj->print();
obj->Append(100);
obj->print();
obj->count();
obj->Append(200);
obj->print();
obj->count();
obj->Append(300);
obj->print();
obj->count();
getch();
}
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Section B
SQL
17. Generate the Electricity Bill for one
consumer.
TABLE CREATION:
SQL>create
table ebill(meter_no varchar(10),c_name varchar(25),bill_date date,units
number(4));
i) VALUE INSERTION:
SQL>insert
into ebill values(‘e1’,’raju’,’17-dec-2019’,46);
ii) CALCULATION OF ELECTRICITY BILL
a) alter
table ebill add(bill_amt number(6,2),due_date date);
b) update
ebill set bill_amt=100+units*4.10 where units<=100;
c) update
ebill set bill_amt=100+100*4.10+(units-100)*5 where units>100;
iii) COMPUTE AND DISPLAY DUE DATE AS BILLING DATE+15 DAYS
SQL>update ebill set due_date=bill_date+15;
SQL>select *from ebill;
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18. Create a student database and compute
the result.
TABLE CREATION:
SQL>create
table student(rollno number(3),name varchar(20),sub1 number(3),sub2 number(3) ,sub3
number(3),sub4 number(3) ,sub5 number(3),sub6 number(3));
i) VALUE INSERTION:
SQL>
insert into student values(1,’deepak’,45,66,75,87,78,98);
SQL>
insert into student values(2,’vani’,45,66,75,87,78,98);
SQL>
insert into student values(3,’raju’,45,66,75,87,78,98);
SQL>
insert into student values(4,’rakshit’,45,66,75,87,78,98);
SQL>
insert into student values(5,’karthik’,45,66,75,87,78,98);
ii) CALCULATION OF TOTAL AND PERCENTAGE:
a) SQL>alter
table student add(total number(3),percentage number(6,2),result varchar(10));
b) SQL>update
student set total=sub1+sub2+sub3+sub4+sub5+sub6;
c) SQL>update
student set percentage=total/6;
iii) COMPUTE RESULT:
a) SQL>update
student set result=’pass’ where(sub1>=35 and sub2>=35 and sub3>=35
and sub4>=35 and sub5>=35 and sub6>=35);
b) SQL>update
student set result=’fail’ where(sub1<35 or sub2<35 or sub3<35 or
sub4<35
or sub5<35 or sub6<35);
iv) a) DISPLAY THE CONTENT OF THE TABLE:
SQL>select * from student;
b) QUERY TO DISPLAY THE LIST OF STUDENTS WHO HAVE PASSED:
SQL>select * from student where result=’pass’;
c) QUERY TO DISPLAY THE LIST OF STUDENTS WHO HAVE FAILED:
SQL>select *from student where result=’fail’;
d) COUNT THE NUMBER OF STUDENTS WHO HAVE PASSED:
SQL>select count(*) from student
where result=’pass’;
e) COUNT NUMBER OF STUDENTS WHO HAVE FAILED:
SQL> select count(*) from student where result=’fail’;
f) COUNT THE NUMBER OF STUDENTS SECURE PERCENTAGE GREATER THAN 60
SQL>select * from student where percentage>60;
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19.
Generate the Employee details and compute the salary based on the department.
e) COUNT NUMBER OF STUDENTS WHO HAVE FAILED:
SQL> select count(*) from student where result=’fail’;
f) COUNT THE NUMBER OF STUDENTS SECURE PERCENTAGE GREATER THAN 60
SQL>select * from student where percentage>60;
EMPLOYEE
TABLE CREATION:
SQL>create table employee(empid
number(4),ename varchar(20),dept_name varchar(20),doj date,salary
number(6,2));
VALUE
INSERTION:
SQL>insert into employee values(1,’ramesh’,’chemistry’,’1-jun-12’,15000);
SQL>insert into employee
values(2,’deepak’,’computer’,’1-jun-14’,16000);
SQL>insert into employee values(3,’rahul’,’computer’,’1-jun-16’,18000);
SQL>insert into employee
values(4,’gopal’,’physics’,’1-aug-19’,20000);
SQL>insert into employee
values(5,’krishna’,’computer’,’1-sep-11’,35000);
i) FIND THE NAMES OF ALL EMPLOYEES WHO WORK FOR COMPUTER DEPARTMENT:
a) SQl>select ename from employee where dept_name=’computer’;
b) HOW MANY EMPLOYEES WORK FOR COMPUTER DEPARTMENT:
SQL>select count(*) from employee where dept_name=’computer’;
ii) USE OF AGGREGATE FUNCTIONS:
a) SQL> select min(salary),max(salary),avg(salary) from employee where dept_name=’computer’;
b) SQL>update employee set salary=salary+10*salary/100 where dept_name=’computer’;
c) SQL>alter table employee add(commission number(6,2));
d) SQL>update employee set commission=5*salary/100;
e) SQL>select * from employee;
BANK TABLE CREATION:
SQL>create table bank(ac_number number(15),c_name varchar(20),ac_type char(2), balance number(15), dot date, t_amount number(15),t_type char(1));
VALUE INSERTION:
SQL>insert into bank
values(123456,’shubham’,’sb’,9000,’18-dec-19’,100,’W’);
SQL>insert into bank values(123451,’shruti’,’ca’,111000,’10-aug-19’,1000,’D’);
SQL>insert into bank values(123452,’kamala’,’sb’,11000,’12-jun-19’,15000,’D’);
SQL>insert into bank values(123453,’sargun’,’ca’,15000,’18-jul-19’,100,’W’);
SQL>insert into bank values(123454,’prashant’,’ca’,150000,’19-oct-19’,1200,’W’);
SQL>insert into bank values(123451,’shruti’,’ca’,111000,’10-aug-19’,1000,’D’);
SQL>insert into bank values(123452,’kamala’,’sb’,11000,’12-jun-19’,15000,’D’);
SQL>insert into bank values(123453,’sargun’,’ca’,15000,’18-jul-19’,100,’W’);
SQL>insert into bank values(123454,’prashant’,’ca’,150000,’19-oct-19’,1200,’W’);
i) FIND THE NAMES OF ALL CUSTOMERS WHOSE BALANCE AMOUNT IS MORE THAN 100000
SQL>select * from bank where balance>100000;
ii) FIND THE NUMBER OF CUSTOMERS WHOSE BALANCE IS LESS THAN MINIMUN i.e. MINIMUM BALANCE IS 1000:
SQL>select count(*) from bank where balance <1000;
iii) TRANSACTION:
SQL>update bank set balance=balance+t_amount where t_type=’D’;
SQL>update bank set balance=balance-t_amount where t_type=’W’;
iv) DISPLAY TRANSACTION ON A PARTICULAR DAY:
SQL>select * from bank where dot=’12-jun19’;
v) DISPLAY ALL THE RECORDS OF SB ACCOUNT:
SQL>select * from bank where ac_type=’sb’;
SECTION C
HTML
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22. Create an HTML program with table and
form.
21. Write a HTML program to create
a study time-table.
<! 21. Write a HTML program to create a study time-table.>
<html>
<body>
<table border="2">
<tr>
<th>monday</th>
<th>tuesday</th>
<th>wednesday</th>
<th>thursday</th>
<th>friday</th>
<th>saturday</th>
</tr>
<tr>
<td>physics</td>
<td>chemistry</td>
<td>mathenatics</td>
<td>biology</td>
<td>kannada</td>
<td>sanskrit</td>
</tr>
<tr>
<td>english</td>
<td>hindi</td>
<td>computer science</td>
<td>mathematics</td>
<td>chemistry</td>
<td>physics</td>
</tr>
<tr>
<td>sanskrit</td>
<td>kannada</td>
<td>biology</td>
<td>physics</td>
<td>chemistry</td>
<td>mathematics</td>
</tr>
<tr>
<td>kannada</td>
<td>physics</td>
<td>mahthematics</td>
<td>biology</td>
<td>chemistry</td>
<td>mathematics</td>
</tr>
</table>
</body>
</html>
<!22. Create an HTML program with table and form.>
<html>
<body>
<h1><center>Application
Form</center></h1>
<form>
First
Name:<input type="text"
value="ram"><br><br>
Last
Name:<input type="text"
value="kumar"><br><br>
Password:<input
type="password"><br><br>
Hidden
Field:<input type="hidden"><br><br>
Address:<textarea
rows="5" cols="20">
My College
Name,
My College
Address
</textarea>
<br><br>
<input
type="checkbox" value="physics">Physics<br>
<input
type="checkbox" value="chemistry">Chemistry<br>
<input
type="checkbox"
value="mathematics">Mathematics<br><br>
Gender:<br>
<input
type="radio" value="male"
name="gender">Male<br>
<input
type="radio" value="female"
name="gender">Female<br><br>
<select>
<option
value="PU-I">PU-I</option>
<option
value="PU-II">PU-II</option>
</select><br><br>
<button
type="submit">Submit</button>
<button
type="reset">Reset</button>
</form>
<html>
<body>
<table
border="2">
<tr>
<th>monday</th>
<th>tuesday</th>
<th>wednesday</th>
<th>thursday</th>
<th>friday</th>
<th>saturday</th>
</tr>
<tr>
<td>physics</td>
<td>chemistry</td>
<td>mathenatics</td>
<td>biology</td>
<td>kannada</td>
<td>sanskrit</td>
</tr>
<tr>
<td>english</td>
<td>hindi</td>
<td>computer
science</td>
<td>mathematics</td>
<td>chemistry</td>
<td>physics</td>
</tr>
<tr>
<td>sanskrit</td>
<td>kannada</td>
<td>biology</td>
<td>physics</td>
<td>chemistry</td>
<td>mathematics</td>
</tr>
<tr>
<td>kannada</td>
<td>physics</td>
<td>mahthematics</td>
<td>biology</td>
<td>chemistry</td>
<td>mathematics</td>
</tr>
</table>
</body>
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2ND PUC COMPUTER SCIENCE LAB PROGRAMS
Reviewed by Vision Academy
on
December 16, 2019
Rating:
Reviewed by Vision Academy
on
December 16, 2019
Rating:
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